An airplane is traveling km/h in a direction 41.5 degrees west of north. (a) find the cmpopnets of the velocity in the northerly and westerly directions. (b) How far north and how far west has the plane traveled after 3.00 h?

You neglected to provide the km/h speed.

To solve this problem, we'll break down the velocity of the airplane into its northern and western components.

(a) To find the components of the velocity, we can use trigonometry. The northern component (Vnorth) can be found by multiplying the speed by the cosine of the angle, and the western component (Vwest) can be found by multiplying the speed by the sine of the angle:

Vnorth = speed * cos(angle)
Vwest = speed * sin(angle)

Given:
Speed (s) = km/h
Angle (θ) = 41.5 degrees west of north

Now we can substitute these values into the formulas:

Vnorth = s * cos(θ)
Vwest = s * sin(θ)

(b) To find how far north and how far west the plane has traveled after 3.00 hours, we need to multiply the components of the velocity by the time:

Distance north = Vnorth * t
Distance west = Vwest * t

Given:
Time (t) = 3.00 hours

Substituting the values, we get:

Distance north = Vnorth * t = (s * cos(θ)) * t
Distance west = Vwest * t = (s * sin(θ)) * t

Now, you can substitute the given values for speed, angle, and time into the formulas, and calculate the northern and western distances traveled by the airplane after 3.00 hours.