L1: (-2,-1), (1,5) L2: (3,5), (5,9) These lines are parallel because they have the same slope but different y-intercepts.(Is this true and if it is how do you solve the problem and graph it)
L1: (-2, -1), (1, 5).
m1=(5 - -(-1)) / (1 - (-2)) = 6/3 = 2
Y = 2(-2) + b = -1,
-4 + b = -1,
b = -1 + 4 = 3,
Eq1: Y = 2X + 3.
L2: (3, 5), (5, 9).
m = (9- 5) / (5 - 3) = 4/2 = 2.
Y = 2*3 + b = 5,
6 + b = 5,
b = 5 - 6 = -1,
Eq2: Y = 2X - 1.
The lines are parallel and have different y-Ints.
The solution would be the point where the 2 lines intersect, but parallel
lines do not intersect. Therefore, there is no solution.