A certain car is capable of accelerating at a uniform rate of 0.85m/s2. What is the magnitude of the car's displacement as it accelerates uniformly from a speed of 83km/h to one of 94km/h?

88.22

To find the magnitude of the car's displacement, we need to calculate the change in position during the acceleration.

First, let's convert the initial and final speeds from km/h to m/s to maintain consistency in units:

Initial speed = 83 km/h = 83 * (1000/3600) m/s = 23.06 m/s
Final speed = 94 km/h = 94 * (1000/3600) m/s = 26.11 m/s

Next, we can use the formula to calculate the displacement during uniform acceleration:

displacement = (vf^2 - vi^2) / (2 * acceleration)

where:
- vf is the final velocity
- vi is the initial velocity
- acceleration is the rate of acceleration

Plugging in the values:
displacement = (26.11^2 - 23.06^2) / (2 * 0.85)

Now, let's simplify the equation:
displacement = (681.6721 - 531.8836) / 1.7
displacement = 149.7885 / 1.7
displacement = 88.11 meters (rounded to two decimal places)

Therefore, the magnitude of the car's displacement as it accelerates uniformly from a speed of 83 km/h to one of 94 km/h is approximately 88.11 meters.