In an electrical circuit, the current passing through a conductor varies inversely with the resistance. Suppose that when the current is 8A (amperes), the resistance is 15 ohms. What is the current when the resistance is 4 ohms?

Please type your subject in the School Subject box. Any other words, including obscure abbreviations, are likely to delay responses from a teacher who knows that subject well.

Well this is a question within the subject I posted. Sorry for not labeling it right

To find the current when the resistance is 4 ohms, we need to use the concept of inverse variation. Inverse variation tells us that when one quantity increases, the other quantity decreases in proportion, and vice versa.

In this case, we are given that the current passing through a conductor varies inversely with the resistance. So, we can set up an equation to represent this relationship:

Current (I) * Resistance (R) = Constant (k)

We can substitute the given values into this equation to find the constant:

8A * 15Ω = k

k = 120

Now that we have the constant, we can use it to solve for the current (I) when the resistance (R) is 4 ohms:

I * 4Ω = 120

I = 120 / 4

I = 30

Therefore, when the resistance is 4 ohms, the current passing through the conductor is 30 amperes.