If a skateboarder is going 40 meters per second after 3 seconds, what is the initial velocity of the skateboarder with an acceleration of 2.1 meters per second squared?
To find the initial velocity of the skateboarder, we can use the following formula of motion:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t))
In this case, the final velocity (v) is given as 40 meters per second, the acceleration (a) is given as 2.1 meters per second squared, and the time (t) is given as 3 seconds.
Using the formula, we can rearrange it to solve for the initial velocity (u):
u = v - (a * t)
Substituting the given values:
u = 40 m/s - (2.1 m/s² * 3 s)
Now, let's calculate it:
u = 40 m/s - 6.3 m/s²
u = 33.7 m/s
Therefore, the initial velocity of the skateboarder is 33.7 meters per second.