A moving electron passes near the nucleus of a gold atom, which contains 79 protons and 118 neutrons. At a particular moment the electron is a distance of 7.5 × 10−9 m from the gold nucleus.

What is the magnitude of the force exerted by the gold nucleus on the electron?

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  1. I seem to recall answering this already.

    F = k*Q1*Q2/R^2 = 79k*e^2/R^2

    (Coulomb's law; k = Coulomb's constant)

    Get to know it

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  2. I'm not getting the answer using this formula. Can you explain it a little more. Thanks

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