If a rectangular prism's length is doubled, it's width quadrupled and it's height stays the same, what is the ratio of the new volume to the original volume?
original volume = lwh
new volume = (2l)(3w)(h) = 6lwh
so, what do you think?
find the volume. round to the nearest cubic unit
To find the ratio of the new volume to the original volume, we need to calculate the volumes of both rectangular prisms.
Let's assume the original length is L, width is W, and height is H.
The original volume (V₁) is given by V₁ = L * W * H.
Now, according to the given information, the new length is twice the original length, so it becomes 2L. The new width is quadrupled, so it becomes 4W. The height remains the same, so it is still H.
The new volume (V₂) is given by V₂ = (2L) * (4W) * H = 8LWH.
To find the ratio, we divide the new volume by the original volume:
Ratio = V₂ / V₁ = (8LWH) / (LWH) = 8.
Therefore, the ratio of the new volume to the original volume is 8:1.