As part of a training program, an athlete runs while holding 8.00 weights in each hand. As he runs, the weights swing through a 30.0 arc in . His hands are 72 from his shoulder joint, and they are light enough that we can neglect their weight compared with that of the 8.00 weight he is carrying.
To find the maximum torque exerted on the athlete's shoulder joint, we can utilize the formula for torque:
Torque = Force × Perpendicular distance
In this case, the force is the weight being carried, which is 8.00 N (assuming the units are in Newtons). The distance is the perpendicular distance from the shoulder joint, which is given as 72 cm (converting it to meters gives 0.72 m).
So, the torque can be calculated as follows:
Torque = 8.00 N × 0.72 m
= 5.76 Nm
Therefore, the maximum torque exerted on the athlete's shoulder joint is 5.76 Nm.