if someone weighs 500 N, how much pressure does she apply when she stands on her head, if the part of her head that is touching the floor has a radius of 2cm?

pressure= weight/area

area=.02^2 * PI m^2

To calculate the pressure exerted when someone stands on their head, we need to divide the force (weight) by the area of contact between their head and the floor. Here's how you can calculate it:

1. Convert the weight from Newtons (N) to kilograms (kg). We can use the formula: weight (in kg) = weight (in N) / acceleration due to gravity (approximately 9.8 m/s^2).

weight (in kg) = 500 N / 9.8 m/s^2
weight (in kg) ≈ 51.02 kg

2. Convert the radius of contact area from centimeters (cm) to meters (m). We use the formula: radius (in m) = radius (in cm) / 100.

radius (in m) = 2 cm / 100
radius (in m) ≈ 0.02 m

3. Calculate the contact area using the formula: area = π * radius^2, where π is approximately 3.14159.

contact area = 3.14159 * (0.02 m)^2
contact area ≈ 0.00126 m^2

4. Finally, calculate the pressure exerted by dividing the weight by the contact area:

pressure = weight (in N) / contact area
pressure ≈ 500 N / 0.00126 m^2
pressure ≈ 396,825.4 N/m^2

Therefore, when someone with a weight of 500 N stands on their head with a head contact area radius of 2 cm, they exert approximately 396,825.4 N/m^2 (or pascals, Pa) of pressure.