Question

Multiple Choice:

Suppose F(x)=∫ from 0 to x^2 of 1/(2+t^3) dt for all real x, then F'(-1)=?
a. 2
b. 1
c. 1/3
d. -2
e. -2/3

Steps please? Thanks(:

Answer 1

F prime is 1/(2+(x^2)^3) * (2x). Then just plug in negative one for x and you get E.