What is the rotational inertia of a 10 kg rod with a length of 0.9m and rotating about an axis passing through its end?
To find the rotational inertia of a rod rotating about an axis passing through its end, we need to use the formula for the rotational inertia of a slender rod.
The formula for the rotational inertia, also known as the moment of inertia, of a slender rod rotating about an axis passing through its end is given by:
I = (1/3) * m * L^2
where:
I is the rotational inertia (moment of inertia)
m is the mass of the rod
L is the length of the rod
In this case, the mass of the rod m is given as 10 kg and the length of the rod L is given as 0.9m. Plugging these values into the formula, we can calculate the rotational inertia:
I = (1/3) * m * L^2
= (1/3) * 10 kg * (0.9m)^2
= (1/3) * 10 kg * 0.81m^2
= 2.7 kg * m^2
Therefore, the rotational inertia of the 10 kg rod rotating about an axis passing through its end is 2.7 kg * m^2.