A gun that shoots bullets at 469m/s is to be aimed at a target 45.7 m away ans level with the gun. How high above the target must the gun barrel be pointed so that the bullet hits the target?
Which equation would I use?
I should have gotten 4.8 cm for the answer...
Find the time it takes to travel that distance:
distance=velocity*time
Then, how far will the bullet drop in that time?
distancefell=1/2 g time^2
To solve this problem, we can use two equations:
1. First, let's find the time it takes for the bullet to travel the distance to the target:
distance = velocity * time
Rearranging the equation to solve for time:
time = distance / velocity
Plugging in the given values:
time = 45.7 m / 469 m/s = 0.0975 seconds
2. Now, let's calculate how far the bullet will drop in that time:
distance_fell = 1/2 * g * time^2
Where g is the acceleration due to gravity, which is approximately 9.8 m/s^2.
Plugging in the values:
distance_fell = 1/2 * 9.8 m/s^2 * (0.0975 s)^2
distance_fell = 0.0476 meters or 4.76 cm
So, based on the calculations, the gun barrel must be pointed approximately 4.76 cm above the target to hit it.