The Everton college store paid 1519 for an order of 41 calculators. The store paid 9 for each scientific calculator. The other, all graphic calculators cost the store 55 each. How many of each type of calculators was ordered?. Thank you
Esther, check your 2-3-11,1:11am post.
X Scientific cal.
Y Graphic cal.
Eq1: X + Y = 41.
Eq2: 9X + 55Y = 1519.
Multiply both sides of Eq1 by -9:
-9X - -9Y = -369,
9X + 55Y = 1519
Add the Eqs:
46Y = 1150,
Y = 1150 / 46 = 25 Graphic cal.
X + 25 = 41,
X = 41 -25 = 16 Scientific cal.
To find out how many of each type of calculator was ordered, let's assume that x represents the number of scientific calculators and y represents the number of graphic calculators.
Given:
The Everton college store paid a total of $1519 for the order.
The store paid $9 for each scientific calculator.
The store paid $55 for each graphic calculator.
The store ordered a total of 41 calculators.
From the given information, we can set up the following equations:
1) The total cost equation: 9x + 55y = 1519
2) The total quantity equation: x + y = 41
To solve this system of equations, we can use the substitution or elimination method.
Let's use the substitution method:
From equation 2, we can isolate x: x = 41 - y
Substituting this value of x into equation 1, we get:
9(41 - y) + 55y = 1519
Expanding the equation, we have:
369 - 9y + 55y = 1519
Combining like terms, we get:
46y = 1150
Dividing both sides of the equation by 46, we have:
y = 25
Now we can substitute the value of y back into equation 2 to find the value of x:
x + 25 = 41
Subtracting 25 from both sides of the equation, we get:
x = 16
Therefore, the Everton college store ordered 16 scientific calculators and 25 graphic calculators.