P= -0.0001x^2+70x-350000 By graphing this what would be the number that would produce a maximum profit. I tried grapghing it but my calculator is not working with me! Is There another way to find the maximum number that would produce the maximum profit?
Yes, there is another way to find the number that would produce the maximum profit without graphing. In this case, you can use algebra to find the maximum point of the quadratic function.
The given function represents a quadratic equation in the form P = ax^2 + bx + c, where P represents profit and x represents the quantity.
To find the number that would produce the maximum profit, you need to find the x-coordinate of the vertex of the quadratic function. The x-coordinate of the vertex is given by the formula x = -b/(2a).
In this case, the equation is P = -0.0001x^2 + 70x - 350000. Comparing it with the form ax^2 + bx + c, we can see that a = -0.0001 and b = 70.
Applying the formula x = -b/(2a), we get:
x = -(70)/(2*(-0.0001))
x = -70/(-0.0002)
x = 350000
So, the number that would produce the maximum profit is 350000.
Remember that this method only provides the x-coordinate of the vertex. To find the actual maximum profit, you would substitute this value back into the original equation P = -0.0001x^2 + 70x - 350000.