Hydrogen gas has been suggested as a clean fuel because it produces only water vapor when it burns. If the reaction has a 95.4% yield, What mass of hydrogen forms 94 Kg of water?
To find the mass of hydrogen gas that forms 94 kg of water, we need to consider the balanced chemical equation for the reaction:
2H₂ + O₂ → 2H₂O
From the equation, we can see that two moles of hydrogen gas (H₂) react with one mole of oxygen gas (O₂) to produce two moles of water (H₂O).
Since we know the molar mass of water is approximately 18 g/mol, we can convert the given mass (94 kg) into moles by using the molar mass:
94 kg of water × (1000 g/1 kg) / (18 g/mol) ≈ 5222.22 moles
Now, since the reaction has a 95.4% yield, only 95.4% of the hydrogen gas will actually be produced. Therefore, we need to multiply the number of moles by the yield:
95.4% yield = 0.954
Number of moles of hydrogen gas = 5222.22 moles × 0.954 ≈ 4984.03 moles
Since two moles of hydrogen gas produce two moles of water, the same number of moles of water will form:
Number of moles of water = 4984.03 moles
Now, we can convert the number of moles of water back into mass by multiplying by the molar mass of water:
Mass of water = 4984.03 moles × 18 g/mol ≈ 89,713.5 g ≈ 89.7 kg
Therefore, approximately 89.7 kg of hydrogen gas will form 94 kg of water.