In a gift wrapping department, a customer can choose from x different papers, y different ribbons, and z different greeting cards. There are 160 different paper, ribbon, and greeting card combinations possible. List three of the possible combinations.
Need help...please.
1 1 1
1 1 2
1 1 3 assuming at least 3 greeting card choices
what is 20+40=
20 + 40 = 60
To find the possible combinations, we can use the concept of multiplication principle. According to the question, there are x different papers, y different ribbons, and z different greeting cards. To get the total number of combinations, we multiply the number of options for each category together.
Therefore, the total number of combinations possible is given by:
Total combinations = x * y * z = 160
Now, you mentioned that there are 160 different combinations possible. However, you did not provide the values of x, y, and z. Without these values, we cannot determine the exact combinations.
Here are three examples of possible combinations assuming x, y, and z are positive integers:
1. If x = 8, y = 5, and z = 4:
Different papers (x) = 8
Different ribbons (y) = 5
Different greeting cards (z) = 4
Total combinations = 8 * 5 * 4 = 160
Possible combination: Paper 1, Ribbon 2, Greeting Card 3
2. If x = 10, y = 4, and z = 5:
Different papers (x) = 10
Different ribbons (y) = 4
Different greeting cards (z) = 5
Total combinations = 10 * 4 * 5 = 200
Possible combination: Paper 5, Ribbon 1, Greeting Card 2
3. If x = 4, y = 8, and z = 5:
Different papers (x) = 4
Different ribbons (y) = 8
Different greeting cards (z) = 5
Total combinations = 4 * 8 * 5 = 160
Possible combination: Paper 2, Ribbon 3, Greeting Card 4
Please provide the values of x, y, and z to determine the exact possible combinations in your specific scenario.