ALgebra...plz help
If the tens digit of a twodigit number is subtracted from the units digit, the difference is 8. The number with the digits reversed is 10 more than nine times the units digit of the original number. Find the number.

Let the two digit number be 10A + B.
Then, from "If the tens digit of a twodigit number is subtracted from the units digit, the difference is 8.", or
B  A = 8.
From "The number with the digits reversed is 10 more than nine times the units digit of the original number.", 10B + A = 9B + 10.
Substituting A = B  8 into 10B + A = 9B + 10 yields 10B + B  8 = 9B + 10 or 11B  8 = 9B + 10 or 2B = 18 making B = 9.
From B  A = 8, 9  A = 8 making A = 1 or the number = 19.
posted by tchrwill

too easy
posted by Anonymous

Let unit digit = x
Then tens did it = 8+x
Original no.is 10(8+x)+x
80+10x+x=80+11x
On reversing : 10x+8+x =11x+8
11x+8=10+9x
11x9x=108
2x=2
X=1
No.is 80+11x=80+11=91posted by Anonymous
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