Questions LLC
Login
or
Sign Up
Ask a New Question
Chemistry
Stoichiometry
Mole-to-mole ratio calculation
How many milliliters of 0.1350 M HCl(aq) will react with 0.066 mol of KMnO4(aq)?
1 answer
See your post above.
You can
ask a new question
or
answer this question
.
Similar Questions
How many milliliters of 0.1350 M HCl(aq) will react with 0.066 mol of KMnO4(aq)?
Top answer:
Do you have the equation. Then follow the steps in the link below.
Read more.
How many milliliters of 0.418 M HCl are needed to react with 52.7 g of CaCO3?
2HCl (aq) + CaCO3 (s) >>> CaCl2 (aq) + CO2 (g) +
Top answer:
Thanks for showing your work. That makes it easier to find the error. You're ok to the last step. I
Read more.
2 KMnO4 + 5 H2C2O4 + 3 H2SO4 ---> 2 MnSO4 + 10 CO2 + 8 H2O + K2SO4
How many milliliters of a 0.123 M KMnO4 solution is needed to
Top answer:
Ok so you take 3.141g and divide that by 90.036?
Read more.
The UNBALANCED equation is: Zn + HCl –] ZnCl2 + H2 How many milliliters of a 0.48 M HCl solution are needed to react
Top answer:
Not quite it. mols Zn = grams/molar mass (Zn, not ZnCl2) Convert mols Zn to mols HCl. That 2 is
Read more.
I need help setting up this problem.
How many milliliters of 0.203 M KMnO4 are needed to react with 3.64 g of iron(II) sulfate,
Top answer:
To solve this problem, you will need to use stoichiometry. Stoichiometry is a mathematical tool used
Read more.
2KMnO4(aq)+16HCl(aq)->2MnCl2(aq)+5Cl2(g)+8H2O(l)+2KCl(aq)
A.)the volume of 0.414 M KMnO4 needed to produce 1.66 mol MnCl2 B.) the
Top answer:
A.) To find the volume of 0.414 M KMnO4 needed to produce 1.66 mol MnCl2, we first need to determine
Read more.
Which of the following mixtures will be a buffer when dissolved in 1 liter of water?
0.10 mol Ba(OH)2 and 0.20 mol HCl 0.30 mol
Top answer:
yes
Read more.
What volume of .0500 M Ba(OH)2 will react completely with 21.00 mL of .500 M HCl?
Same type problem. Post your work if you get
Top answer:
To calculate the volume of 0.0500 M Ba(OH)2 required to react completely with 21.00 mL of 0.500 M
Read more.
1.38 mol HCl and 2.9 mol NaOH react accord-
ing to the equation HCl + NaOH −→ NaCl + H2O . If the limiting reactant is HCl,
Top answer:
I answered this for you last night. Look for your other post below.
Read more.
1.38 mol HCl and 2.9 mol NaOH react accord-
ing to the equation HCl + NaOH −→ NaCl + H2O . If the limiting reactant is HCl,
Top answer:
mol HCl initially = 1.38 mol NaOH initially = 2.90 mol NaOH after reacting = 2.90 - 1.38 = ? mols.
Read more.
Related Questions
A 1.00 g sample of limestone is allowed to react with 100 cm^3 of 0.200 mol/dm^3 HCl. The excess acid required 24.8 cm^3 of
A sample of impure magnesium was analyzed by allowing it to react with excess HCl solution:
Mg(s) + 2 HCl(aq) → MgCl2(aq) +
Perpare 500ml of 1M HCl solution from a bottle of concentrated 37%(W/W) HCL stock with a density of 1.19g/ml.
37%= 37/100 x 100
According to the reaction 2Al+3H2SO4→3H2+Al2(SO4)3, the total number of moles of H2SO4 needed to react completely with 5.0 mol
Given a percent yield of 45.0% for the reaction:
H2 + Cl2 → 2 HCl(g) How many moles of HCl gas are produced if 15.5 L of Cl2 at
how many milliliters of a 0.9 molar HCl solution are needed to react completely with 12 grams of zinc according to the following
6 FeCl2(aq) + K2Cr2O7(aq) + 14 HCl(aq) ==>
6 FeCl3(aq) + 2 CrCl3(aq) + 2 KCl(aq) + 7 H2O(l) How many milliliters of 0.0750 M
How many milliliters of a 0.75 M HCL solution do you need to obtain 0.0040 mol of HCL?
If 10mL of 1 M HCl is added to 1L of 0.01 M phosphate buffer, pH 7.2, what is the resulting pH?
Also what are the conc of
Chlorine gas can be prepared according to the reaction: 16 HCl+2KMnO4->2MnCl2+8H2O When 25g HCl react with 25 g KMnO4, how many