Calculate the volume of Sulfur dioxide produced when 27.9 mL of O2 reacts with carbon disulfide

To calculate the volume of sulfur dioxide (SO2) produced when a certain amount of O2 reacts with carbon disulfide (CS2), we need to use the balanced chemical equation for the reaction:

2 O2 + 2 CS2 -> 2 SO2 + 2 CO2

From the equation, we can see that the ratio between the volume of O2 and the volume of SO2 produced is 2:2 or simply 1:1. Therefore, the volume of SO2 produced will be equal to the volume of O2 used.

Given that the volume of O2 used is 27.9 mL, we can conclude that the volume of SO2 produced will also be 27.9 mL.

Thus, the volume of sulfur dioxide produced when 27.9 mL of O2 reacts with carbon disulfide is 27.9 mL.

To calculate the volume of sulfur dioxide (SO2) produced when O2 reacts with carbon disulfide (CS2), we need to use the balanced chemical equation and the volume ratio.

The balanced chemical equation for the reaction between O2 and CS2 is:
O2 + CS2 -> CO2 + SO2

According to the equation, for every 1 mole of O2, we get 1 mole of SO2.

To calculate the volume of SO2, we need to convert the given volume of O2 to moles and use the mole ratio from the balanced equation.

1. Convert the given volume of O2 to moles:
The molar volume of any gas at standard temperature and pressure (STP) is 22.4 L/mol.
27.9 mL of O2 is equal to 27.9 / 1000 = 0.0279 L (converting mL to L).
Now, we can calculate the number of moles of O2:
moles of O2 = volume of O2 / molar volume
moles of O2 = 0.0279 L / 22.4 L/mol
moles of O2 ≈ 0.00124375 mol (approximately)

2. Use the mole ratio from the balanced equation:
From the balanced equation, we know that 1 mole of O2 produces 1 mole of SO2.

Therefore, the moles of SO2 produced will also be 0.00124375 mol.

3. Calculate the volume of SO2:
Using the molar volume at STP, we can convert the moles of SO2 to volume:
volume of SO2 = moles of SO2 × molar volume
volume of SO2 = 0.00124375 mol × 22.4 L/mol
volume of SO2 = 0.0278 L (approximately)

Hence, the volume of sulfur dioxide produced when 27.9 mL of O2 reacts with carbon disulfide is approximately 0.0278 L.

Here is a worked example of a stoichiometry problem. Just follow the steps.

http://www.jiskha.com/science/chemistry/stoichiometry.html