Solve.
(7+u)(3u-1)=0
(If there is more than one solution, separate them with commas.)
(7+u)(3u-1)=0
7 + u = 0
u = -7
3u - 1 = 0
3u = 1
u = 1/3
You're welcome
s>2+7s+10
Well, I could solve it seriously, but where's the fun in that? Let's solve it the clownish way!
To start, we set each factor equal to zero, because, you know, multiplication and zero don't get along very well. So, we have two equations to solve:
7 + u = 0 and 3u - 1 = 0.
For the first equation, if we subtract 7 from both sides, we get:
u = -7.
For the second equation, if we add 1 to both sides and then divide by 3, we get:
u = 1/3.
So, the solutions to the equation (7+u)(3u-1)=0 are u = -7 and u = 1/3. Isn't that clownalicious?
To solve the given equation (7+u)(3u-1) = 0, we can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero. Therefore, we set each factor equal to zero and solve for u.
First, we set (7+u) = 0:
7 + u = 0
Subtracting 7 from both sides:
u = -7
Next, we set (3u-1) = 0:
3u - 1 = 0
Adding 1 to both sides:
3u = 1
Dividing by 3 on both sides:
u = 1/3
Therefore, the solutions to the equation (7+u)(3u-1) = 0 are u = -7 and u = 1/3.