# Math

A 30% solution of fertilizer is to be mixed with a 60% solution of fertilizer in order to get 150 gallons of 50% solution. How many gallons of the 30% and the 60% solutions should be mixed. I really need help.

1. 0
2. 9
1. x = gal of 30% solution
.30x = value of 30% solution
150 - x = gal of 60% solution
.60(150 - x)
.50(150) = mixture

.30x + .60(150 - x) = .50(150)

Solve for x, gal of 30% solution
150 - x = gal of 60% solution

1. 0
posted by helper

## Similar Questions

1. ### math

mrs. lemeke has 10 2/3 ounces of fertilizer . she plans to use 3/4 ounce of fertilizer on each plant. After she puts fertilizer on as many plants as she can, how much fertilizer will be left over?
2. ### math

I'm not sure of how to solve word problems. The question is,"One lawn fertilizer is 24% nitrogen and another is 12% nitrogen. How much of fertilizer should be mixed to obtain 100 kg of fertilizer that is 21% nitrogen?"
3. ### math

I'm not sure of how to solve word problems. The question is,"One lawn fertilizer is 24% nitrogen and another is 12% nitrogen. How much of fertilizer should be mixed to obtain 100 kg of fertilizer that is 21% nitrogen?"
4. ### math

Before it can be used, a 12-ounce container of liquid fertilizer must be mixed with 48 ounces of water. What fraction of fertilizer is in the final mixture?
5. ### CHEMISTRY

A garden fertilizer contains 15% by mass of nitrogen. The recommended usage is 30g of fertilizer per 10dm^3 of water. What is the concentration of nitrogen in this solution? a)0.15 g dm^-3 b)0.30 g dm^-3 c)0.45 g dm^-3 d)3.00 g
6. ### Science

A farmer wants to determine if a new fertilizer gives her a better crop yield than her old fertilizer. She spreads the old fertilizer in field A, which has a brand new irrigation system. She spreads the new fertilizer in field B,
7. ### Science

A farmer wants to determine if a new fertilizer gives her a better crop yield than her old fertilizer. She spreads the old fertilizer in field A, which has a brand new irrigation system. She spreads the new fertilizer in field B,