Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
6-inch side.
A = sq. in.
Draw a straight line from the mid point of one side to the opposite vertex.
Use the Pythagorean Theorem to find the length of this line. Let b = this line (the height).
a^2 + b^2 = c^2
3^2 + b^2 = 6^2
9 + b^2 = 36
b^2 = 27
b = 5.2
Now use this formula to find the area of this triangle.
A = 1/2bh
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What is the area of a equlateral triangle with the measurement of 6-inch side?
To find the area of an equilateral triangle with a 6-inch side, you can use the formula:
A = (s^2 * sqrt(3)) / 4
where A represents the area and s represents the length of one side of the equilateral triangle.
Substituting the given measurement, we get:
A = (6^2 * sqrt(3)) / 4
A = (36 * sqrt(3)) / 4
Now, let's simplify the expression:
A = (9 * sqrt(3))
So, the area of an equilateral triangle with a 6-inch side is 9√3 square inches.