Use the rational zeros theorem to list all possible rational zeros of the following.

-2x^3-x^2-4x-5
I got +-1,+-5+-,5/2,+-1/2
Be sure that no value in your list appears more than once.

Yes, you have applied the theorem correctly. Not all of those possibilites are actual solutions, however. The only rational real solution is -1.

I see what I did, Thanks

To list all possible rational zeros using the rational zeros theorem, we need to find all the possible factors of the constant term (-5) divided by all possible factors of the leading coefficient (-2).

The possible factors of -5 are:
±1, ±5

The possible factors of -2 are:
±1, ±2

Dividing all possible factors of the constant term (-5) by all possible factors of the leading coefficient (-2), we get the following possible rational zeros:

±1/1, ±1/2, ±5/1, ±5/2

Therefore, the list of all possible rational zeros is:
±1, ±1/2, ±5, ±5/2

To find the possible rational zeros of a polynomial using the Rational Zeros Theorem, we need to consider the factors of the constant term divided by the factors of the leading coefficient.

For the given polynomial: -2x^3 - x^2 - 4x - 5

Constant term = -5
Factors of constant term = ±1, ±5

Leading coefficient = -2
Factors of leading coefficient = ±1, ±2

Now, we can list all possible rational zeros using the combinations of the factors:

±1/1, ±5/1, ±1/2, ±5/2

Simplifying these expressions, we get:

±1, ±5, ±1/2, ±5/2

Removing any repeated values from the list, we have the possible rational zeros as:

±1, ±5, ±1/2, ±5/2