A student makes a solution by dissolving 55.8 grams of potassium hydroxide in 875.0 grams of water. The resulting solution has a density of 1.07 grams per milliliter.
1. What is the volume of this solution?
2. Calculate the % concentration of this solution.
3. Calculate the molar concentration of this solution.
4. How many grams of potassium hydroxide are there in 150.0ml of this solution?
5. A 200.0ml sample of this solution is diluted to 500.0ml with water. What is its molar concentration?
6. What volume of this solution contains 12.75 grams of potassium hydroxide?
7. What mass of the original solution contains 25.0 grams of potassium hydroxide?
8. What volume of 0.750M H2SO4 solution can be neutralized by 100.0 grams of this solution?
9. A student needs 0.600L a 0.100M solution of potassium hydroxide. Describe how this can be done using the original solution and a 1000ml graduated cylinder.
Instead of us working nine problems for you to check you answers, tell us what you don't understand about each and we can help you through the hard spots. The first one is mass = volume x density. Substitute and solve for the unknown volume.
52.15
1. To determine the volume of the solution, we can use the formula:
Volume (in milliliters) = Mass (in grams) / Density (in grams per milliliter)
Here, the mass of the solution is the sum of the mass of potassium hydroxide and water:
Mass of solution = Mass of KOH + Mass of water
2. To calculate the percent concentration of the solution, we need to find the ratio of the mass of potassium hydroxide to the total mass of the solution, and then multiply by 100:
% Concentration = (Mass of KOH / Mass of solution) * 100
3. To calculate the molar concentration of the solution, we need to use the formula:
Molar concentration (in moles per liter) = (Mass of KOH / Molar mass of KOH) / Volume of solution (in liters)
4. To determine the grams of potassium hydroxide in 150.0ml of the solution, we need to find the amount of potassium hydroxide per unit volume and then multiply by the desired volume:
Grams of KOH = (Mass of KOH / Volume of solution) * Desired volume
5. To find the molar concentration of the diluted solution, we can use the formula:
Molar concentration (in moles per liter) = (Molar concentration of original solution * Volume of original solution) / Volume of diluted solution
6. To determine the volume of the solution that contains 12.75 grams of potassium hydroxide, we can rearrange the formula for molar concentration:
Volume of solution = (Mass of KOH / Molar mass of KOH) / Molar concentration
7. To find the mass of the original solution that contains 25.0 grams of potassium hydroxide, we can use the same formula from question 4:
Mass of solution = (Mass of KOH / Volume of solution) * Desired volume
8. To determine the volume of 0.750M H2SO4 solution that can be neutralized by 100.0 grams of the given solution, we need to use the reaction equation between the two substances and the stoichiometry:
Volume of H2SO4 solution = (Molar concentration of H2SO4 * Volume of H2SO4 solution * Moles of KOH) / Molar ratio
9. To prepare a 0.100M solution of potassium hydroxide using the original solution and a 1000ml graduated cylinder, you can use the formula:
Volume of original solution = (Desired Molarity / Original Molarity) * Desired Volume
In this case, the original volume is given as 875.0 grams, which converts to milliliters using the density. You can then subtract the volume of KOH solution obtained from the desired volume using the graduated cylinder.