i have 2 solve by elimination an i keep gettin fractions when the answer is (-3,-3)

my teacher gave me the answer an problem but she wants me 2 work it out
idk how i keep gettin fractions
the problem is:
-3x-4y=21
8x-5y=-9

please help

Multiply by -5 (-3x - 4y = 21)

Multiply by 4 (8x - 5y = -9)

15x + 20y = -105
32x - 20y = -36
47x + 0 = -141
47x = -141
x = -3

8x - 5y = -9
x = -3
8(-3) - 5y = -9
-24 - 5y = -9
-5y = 15
y = -3

ty

To solve the system of equations using elimination, you need to eliminate one variable by manipulating the equations. Let's go step by step to solve the given system of equations:

Step 1: Multiply the first equation by 8 and the second equation by -3 to make the coefficients of x in both equations opposites of each other:

-24x - 32y = 168
-24x + 15y = 27

Step 2: Now, subtract the second equation from the first equation to eliminate the x variable:

(-24x - 32y) - (-24x + 15y) = 168 - 27

Simplifying the equation:

-24x - 32y + 24x - 15y = 141

Combine the like terms:

-47y = 141

Step 3: Divide both sides of the equation by -47 to solve for y:

y = 141 / -47

Simplifying the fraction:

y = -3

Step 4: Substitute the value of y into one of the original equations to solve for x. Let's use the first equation:

-3x - 4(-3) = 21

Simplifying the equation:

-3x + 12 = 21

Subtract 12 from both sides:

-3x = 21 - 12

Simplifying:

-3x = 9

Step 5: Divide both sides by -3 to solve for x:

x = 9 / -3

Simplifying, you get:

x = -3

So the solution to the given system of equations is x = -3 and y = -3, which matches the answer you were provided with.

If you were getting fractions in your calculations, it is possible that there might have been an error during the simplification or calculation process. Double-check your work, paying attention to arithmetic calculations, negative signs, and operations with fractions.