2h2o2(aq) ---> 2h2o(l) + o2(g)
if someone puts 0.470 ml of hydrogen peroxide on a cut how many moles of hydrogen peroxide are used? Assume the density of the solution is equal to the density of water.
Normally, the "hydrogen peroxide" one buys over the counter is 3 percent.
To determine the number of moles of hydrogen peroxide used, we need to use its density and the given volume.
First, let's convert the volume of hydrogen peroxide from milliliters (ml) to liters (L):
0.470 ml = 0.470/1000 L (since there are 1000 milliliters in a liter)
= 0.000470 L
Given that the density of the hydrogen peroxide solution is equal to the density of water, we can use the density of water, which is approximately 1 g/ml or 1000 kg/m³, to calculate the mass of the solution.
The mass of the solution can be calculated by multiplying the volume by the density:
Mass = Volume x Density
= 0.000470 L x 1000 g/L (since the density is 1 g/ml)
= 0.470 g
Now, we need to convert the mass of hydrogen peroxide to moles. The molar mass of hydrogen peroxide (H2O2) is:
H = 1.008 g/mol
O = 16.00 g/mol
Molar mass of H2O2 = (2 x H) + (2 x O) = (2 x 1.008) + (2 x 16.00) = 34.014 g/mol
Now we can calculate the number of moles of hydrogen peroxide:
Moles = Mass / Molar mass
= 0.470 g / 34.014 g/mol
≈ 0.0138 mol
Therefore, approximately 0.0138 moles of hydrogen peroxide are used when someone puts 0.470 ml of hydrogen peroxide on a cut.