If a solar cell with 2 m^2 surface area is placed in a direct light having 780 W/m power density provides an output power of 346 W, what is the efficiency in percent? (0 to 100 %, no decimals). Provide your answer in base units (no scientific notation or magnitude modifiers like k or M). Use the abbreviation for the unit not the full unit name.
To find the efficiency of the solar cell, we need to calculate the ratio of the output power to the input power.
First, we need to calculate the input power. The power density is given as 780 W/m², and the surface area of the solar cell is 2 m². Therefore, the input power can be calculated as:
Input Power = Power Density × Surface Area
Input Power = 780 W/m² × 2 m²
Input Power = 1560 W
Now, we can calculate the efficiency:
Efficiency = (Output Power / Input Power) × 100
Efficiency = (346 W / 1560 W) × 100
Efficiency = 0.221795 × 100
Efficiency ≈ 22.18
Therefore, the efficiency of the solar cell is approximately 22.18%.