Could someone help me with these problems;

A)If 5.97mL of a solution of NaCl contains 2.54g of sodium ion, what is the molarity of the sodium chloride solution?
-I know M=#moles solute/L
but when I do this I get 7.28*10^-3 which is wrong, the answer should be 1.85*10^-2

B) Combustion analysis of a 22.0-mg sample of the painkiller morphine produced 13.2 mg of water. What is the % by mass of hydrogen in morphine?

A) Ah, the wonders of chemistry! Let's calculate the molarity of the sodium chloride solution. First, we need to find the number of moles of sodium ion present. We can use the equation: moles = mass / molar mass. The molar mass of sodium ion is 22.99 g/mol. So, moles = 2.54 g / 22.99 g/mol = 0.1104 mol.

Next, we need to find the volume of the solution in liters. 5.97 mL is equivalent to 5.97 x 10^-3 L.
Now we can calculate the molarity using the formula: M = moles / volume. This gives us M = 0.1104 mol / 5.97 x 10^-3 L. The calculation gives 18.46 M, but that's a bit extreme for a solution, don't you think? So, I suspect there might have been a calculation error somewhere, as you mentioned. Perhaps check your conversions, and be sure to use the correct unit for the molarity.

B) Ah, morphine, a real painkiller in more ways than one! To find the mass percent of hydrogen in morphine, we need to determine the mass of hydrogen and the mass of the entire compound. We know that the mass of water produced from the combustion is 13.2 mg, and this is only from the hydrogen atoms in the morphine molecule. So, the percentage is: (13.2 mg / 22.0 mg) x 100%. This evaluates to be 60% - a significant amount of water to carry around in painkiller molecules! It seems like morphine is keeping hydrated, wouldn't you agree?

A) To find the molarity of the sodium chloride solution, we need to calculate the number of moles of sodium ions present in the solution. Given that 5.97 mL of the solution contains 2.54 g of sodium ions, we can use the molar mass of sodium ion (22.99 g/mol) to calculate the number of moles.

First, convert the volume of the solution from mL to L:
5.97 mL = 5.97 × 10^-3 L

Next, use the given mass of sodium ions (2.54 g) to calculate the number of moles:
moles = mass / molar mass
moles = 2.54 g / 22.99 g/mol

Now, we can calculate the molarity (M):
M = moles / volume
M = (2.54 g / 22.99 g/mol) / (5.97 × 10^-3 L)

Calculating this value will give you the molarity of the sodium chloride solution.

B) To find the percent by mass of hydrogen in morphine, we need to compare the mass of hydrogen to the total mass of the compound. Given that 22.0 mg of morphine produced 13.2 mg of water, we can calculate the mass of hydrogen in the water.

Since water (H2O) has a molar mass of 18.02 g/mol and consists of 2 hydrogen atoms per molecule, we can use this information to calculate the mass of hydrogen in 13.2 mg of water.

First, calculate the number of moles of water:
moles = mass / molar mass
moles = 13.2 mg / 18.02 g/mol

Next, use the mole ratio of hydrogen to water to find the number of moles of hydrogen:
moles of hydrogen = moles of water × 2

Now, calculate the mass of hydrogen in morphine by converting the number of moles to mass:
mass of hydrogen = moles of hydrogen × molar mass of hydrogen

Finally, to find the percent by mass of hydrogen in morphine, divide the mass of hydrogen by the mass of morphine (22.0 mg) and multiply by 100%.

This will give you the percent by mass of hydrogen in morphine.

Certainly! I can help you with these problems. Let's go through them step by step.

A) To find the molarity of the sodium chloride solution, we need to calculate the number of moles of sodium ion (Na+) first. Then we can use the formula: Molarity (M) = moles of solute / liters of solution.

Given:
Volume of solution (V) = 5.97 mL = 5.97 x 10^-3 L
Mass of sodium ion (m) = 2.54 g
Molar mass of Na+ = 22.99 g/mol

To find the moles of sodium ion, we can use the formula: moles = mass / molar mass.
So, moles of Na+ = 2.54 g / 22.99 g/mol = 0.1105 mol

Now we can calculate the molarity of the sodium chloride solution:
Molarity (M) = moles of solute / liters of solution
= 0.1105 mol / 5.97 x 10^-3 L
= 18.47 M

The molarity of the sodium chloride solution is 18.47 M. However, I notice that the answer you provided is different. Please double-check your calculations to ensure accuracy.

B) To find the percent by mass of hydrogen in morphine, we need to calculate the mass of hydrogen in the 22.0 mg sample of morphine and then divide it by the mass of the entire sample.

Given:
Mass of morphine (m) = 22.0 mg
Mass of water produced (m_water) = 13.2 mg
Molar mass of water (H2O) = 18.02 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol

First, let's calculate the moles of water produced using the formula: moles = mass / molar mass.
Moles of water (moles_water) = 13.2 mg / 18.02 g/mol = 0.7321 mol

Since water contains two moles of hydrogen per mole of water, we can determine the moles of hydrogen as follows:
Moles of hydrogen (moles_H) = 2 * moles_water = 2 * 0.7321 mol = 1.4642 mol

Next, we calculate the mass of hydrogen:
Mass of hydrogen (mass_H) = moles_H * molar mass of hydrogen
= 1.4642 mol * 1.01 g/mol
= 1.4801 g

Now, we can calculate the percent by mass of hydrogen in morphine:
Percent by mass of hydrogen = (mass_H / mass of morphine) * 100
= (1.4801 g / 22.0 mg) * 100
= 6.7273%

Therefore, the percent by mass of hydrogen in morphine is approximately 6.73%. Again, please double-check your calculations to ensure accuracy.

If you have any further questions or need clarification, feel free to ask!

If you had shown your work I could have found your error; however, I suspect the error you made was to divide 2.54 g by molar mass NaCl (about 58.5) whereas the problem states that it is 2.54 g of the Na^+. So 2.54/23 = moles NaCl.

There is a bigger problem than that. Could you have made a typo and the 2.54 g whould be 2.54 mg? If so then
2.54 mg/23 = ?? mmoles and ??mmoles/5.97 mL = 0.0185 M.
But if 2.54g is correct, then
2.54/23 = 0.110 moles and that divided by 0.00597 L = a number 100 x higher than the answer. Of course, that could be 5.97L too for the correct answer to be 0.0185M