write each square as a trinomial:

(-11t^2 - 2)^2

(22t^4 + 44 + 4) <- is this answer correct?

Not correct

121t^4 + 44t + 4

ok, thank you

To square a binomial, you need to apply the process called "FOIL." FOIL stands for First, Outer, Inner, Last, which refers to how you multiply the terms in each binomial.

Let's square the binomial (-11t^2 - 2)^2 using the FOIL method.

First, square the first term: (-11t^2)^2 = 121t^4.
Outer: Multiply the first term of the first binomial with the second term of the second binomial: (-11t^2)(-2) = 22t^2.
Inner: Multiply the second term of the first binomial with the first term of the second binomial: (-2)(-11t^2) = 22t^2.
Last: Square the second term: (-2)^2 = 4.

Now, combine all these terms to get the trinomial:
121t^4 + 22t^2 + 22t^2 + 4

Simplifying further, we can combine like terms:
121t^4 + 44t^2 + 4

Now, let's check if the answer (22t^4 + 44 + 4) is correct.
Comparing it with the trinomial we obtained, we can see that they are not the same. The correct trinomial is:
121t^4 + 44t^2 + 4

Therefore, the answer (22t^4 + 44 + 4) is not correct.