What volume does a mixture of 14.2g of helium and 21.6g of hydrogen gas occupy at 28 degrees celcius and .985atm?
Convert 14.2 g He and 21.6g H2 to moles, add them, and substitute them for n into PV = nRT. Solve for V.
My number is 358 when rounded to 3 s.f. Check your figures. I did not round the molar masses.
I almost forgot. Note the correct spelling of celsius.
Oh, helium and hydrogen gas walk into a bar... The bartender looks at them and says, "Sorry, we don't serve your mixture here." Helium and hydrogen gas gasp in shock and reply, "Oh, come on! We just want to know the volume we occupy!"
Alright, alright, here's the deal: To calculate the volume, we need to use the ideal gas law equation: PV = nRT. But luckily for you, I've already done the math and I've found out that your mixture would occupy approximately "That's classified!" Oops, sorry. I was sworn to secrecy by the helium and hydrogen gas union. I tried to negotiate, but they can be quite gaseous.
To find the volume of the gas mixture, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
1. First, let's convert the temperature from degrees Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, 28 degrees Celsius is equal to 28 + 273.15 = 301.15 Kelvin.
2. Next, let's calculate the number of moles of each gas using their respective masses and molar masses. The molar mass of helium (He) is 4.00 g/mol, and the molar mass of hydrogen (H₂) is 2.02 g/mol.
Number of moles of Helium (He):
moles = mass / molar mass = 14.2 g / 4.00 g/mol = 3.55 mol
Number of moles of Hydrogen (H₂):
moles = mass / molar mass = 21.6 g / 2.02 g/mol = 10.69 mol
3. Now, let's calculate the total number of moles of the gas mixture:
Total moles = moles of Helium + moles of Hydrogen = 3.55 mol + 10.69 mol = 14.24 mol
4. We can rearrange the ideal gas law equation to solve for volume (V):
V = (nRT) / P
Substitute the known values:
V = (14.24 mol) * (0.0821 L·atm/mol·K) * (301.15 K) / 0.985 atm
Calculating this will give us the volume (V) in liters.
Thus, solving the equation, we find that the volume of the gas mixture is approximately V ≈ 427.27 liters.