A bank teller is counting his money and notices that he has an equal number of tens and twenties. He also had $147 in other bills. If the total value of the bills he has is $1,167, how many tens and twenties does he have
What would be the equation in algebra?
To solve this problem, we can set up a system of equations. Let's assume the number of tens is represented by 'x' and the number of twenties is represented by 'y'.
According to the problem, we know that:
1. The number of tens is equal to the number of twenties: x = y
2. The total value of the bills he has is $1,167: 10x + 20y + 147 = 1167
Now, we can solve this system of equations to find the values of 'x' and 'y'.
Substituting the value of x in the second equation, we get:
10y + 20y + 147 = 1167
30y + 147 = 1167
30y = 1167 - 147
30y = 1020
y = 1020/30
y = 34
Now, substituting the value of y back into the equation x = y, we get:
x = 34
Therefore, the bank teller has 34 tens and 34 twenties.
$1167 ttl value of bills
$147 ttl value of other bills
$1020 value of tens and twenties
n = number of tens and twenties
10n = ttl value of tens
20n = ttl value of twenties
10n + 20n = 1020
Solve for n, number of tens and twenties
(equal number of both)