If the sum of the sides of a right triangle is 49 inches and the hypotenus is 41 inches, then what would be the other two sides?
49-41=8
7+1
6+2
5+3
4+4
Do you mean that the two unknown sides total 49, or all three sides total 49?
That is possible combinations, but in right triangle c^2=a^2+b^2
41=a^2+b^2
a=4 b=5
41=5^2+4^2
41=25+16
Other two sides is 4 and 5
41+4+4=49
It could be,
9 + 40 = 49
a^2 + b^2 = 41^2
a + b = 49
Solving simultaneously
a = 9, b = 40 or
a = 40, b = 9
41^2 = 9^2 + 40^2
1681 = 81 + 1600
1681 = 1681
To find the lengths of the other two sides of a right triangle, you can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
Let's assign variables to the lengths of the other two sides. Let's call one side "a" and the other side "b". We are given that the hypotenuse (c) has a length of 41 inches, and the sum of all three sides is 49 inches. So, we have:
a + b + c = 49 inches
a + b + 41 = 49
Now, we can use the Pythagorean theorem to find the values of "a" and "b". Since the hypotenuse is 41 inches, we have the equation:
a^2 + b^2 = c^2
a^2 + b^2 = 41^2
This gives us two equations:
a + b + 41 = 49
a^2 + b^2 = 41^2
Solving these equations simultaneously will give us the values of "a" and "b".