i just need to know if i got the right answer. plz thankyou
a 15000N car on a hydrolyic lift rests on a cylinder with a piston of radius 0.20M,. if a connecting cylinder with a piston of 0.04M radius is driven by compressed air, what force must be applied to the smaller piston in order to lift the car?
am i doing this right?
pi*(0.04M)^2 / pi(0.20M)^2* 15000N = 600N
is this right, if not how do i go about getting the right anwser?
Yes, correct. Pressure (force/area) is the same on each piston.
To verify if your calculation is correct, let's go through the steps one by one.
1. First, let's calculate the area of the larger piston (A1) using the formula:
A1 = π * (radius of the larger piston)^2
Substituting the values, we get:
A1 = π * (0.20M)^2 = 0.1256m^2
2. Next, let's calculate the area of the smaller piston (A2) using the same formula:
A2 = π * (radius of the smaller piston)^2
Substituting the values, we get:
A2 = π * (0.04M)^2 = 0.0050m^2
3. Now, we can calculate the force required to lift the car (F2) using the formula:
F2 = (Force on larger piston / Area of larger piston) * Area of smaller piston
Substituting the given force on the larger piston (F1 = 15000N), and the calculated areas, we get:
F2 = (15000N / 0.1256m^2) * 0.0050m^2
= 600N
Based on the calculations, your answer of 600N is correct. Well done!