A new "D" battery has an emf of 1.5 V. When a wire of negligible resistance is connected between the terminals of the battery, a current of 25 A is produced. Find the internal resistance of the battery.

________ Ω

Ali-1, check your 1-25-11, 5:37pm post.

To find the internal resistance of the battery, we can use Ohm's Law. Ohm's Law states that the voltage across a component is equal to the current flowing through it multiplied by its resistance.

In this case, the voltage across the internal resistance of the battery is equal to the product of the current flowing through it and the internal resistance. The voltage across the internal resistance is the difference between the electromotive force (emf) of the battery and the voltage across the wire.

Let's denote the internal resistance of the battery as "r", the current flowing through the wire as "I", and the emf of the battery as "E".

According to Ohm's Law, we have the equation:

E = I(R + r)

Where:
E = emf of the battery = 1.5 V
I = current flowing through the wire = 25 A
R = resistance across the wire (negligible in this case)
r = internal resistance of the battery (what we want to find)

To find the internal resistance, we rearrange the above equation as:

r = (E - I * R) / I

Since the resistance across the wire is negligible, we can ignore it, and the equation becomes:

r = E / I

Substituting the given values, we have:

r = 1.5 V / 25 A

Calculating the division, we find that:

r ≈ 0.06 Ω

Therefore, the internal resistance of the battery is approximately 0.06 Ω.

To find the internal resistance of the battery, we need to use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) across the circuit divided by the resistance (R) of the circuit.

In this case, the voltage across the circuit is the emf of the battery (𝐸 = 1.5 V), and the current flowing through the circuit is 25 A.

We can set up the equation as follows:

I = E / R

Plugging in the known values:

25 A = 1.5 V / R

Now, solve for the internal resistance (R):

R = 1.5 V / 25 A

R = 0.06 Ω

Therefore, the internal resistance of the battery is 0.06 Ω.

Learn and apply Ohm's Law.

V = I R, or

R = V/I