write an equation of the line containing the given point and perpendicular to the given line (6,7);6x+=9
I am having a terrible time figuring out the last part. I would appreciate any help. Thank you.
Your equation is not complete.
6x + = 9?
Sorry, I'm stressing badly. The equation is (6,7);6x+y=9. Thank you kindly.
(6,7);6x+y=9.
y = mx + b
6x + y = 9
y = -6x + 9
m = -6
m1*m2 = -1
-6*m2 = -1
m2 = 1/6
So, the slope of the perpendicular line is 1/6.
y = 1/6 x + b
Now find b with point (6,7).
y = 1/6 x + b
7 = 1/6 (6) + b
7 = 6/6 + b
7 = 1 + b
b = 6
y = 1/6 x + b
y = 1/6 x + 6
Was ist der dritte Teil von x?
Stefanie, I need to turn in my homework today and i still need to solve this problem, can you please help me?(4,-8); 2x+5y=4
Thank you for your understanding.
To find the equation of a line perpendicular to a given line, we need to determine the slope of the given line and then find the negative reciprocal of that slope. The negative reciprocal is the value obtained by taking the reciprocal of the slope and changing its sign.
Given the equation of the line: 6x + y = 9
To determine the slope of the line, we need to rewrite the equation in the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.
Rearranging the equation: y = -6x + 9
From this equation, we can determine that the slope of the given line is -6. The negative reciprocal of -6 is 1/6.
Now, we have the slope of the line perpendicular to the given line, which is 1/6. We also have a point on the line, which is (6,7).
To find the equation of the line perpendicular to the given line that passes through the point (6,7), we use the point-slope form of a linear equation:
y - y₁ = m(x - x₁)
where (x₁, y₁) represents the coordinates of the given point, and m represents the slope of the line.
Plugging in the values, we get:
y - 7 = (1/6)(x - 6)
Now, let's simplify the equation:
y - 7 = (1/6)x - 1
By rearranging the equation, we obtain the final equation in slope-intercept form:
y = (1/6)x + 6
Therefore, the equation of the line perpendicular to 6x + y = 9 and passing through the point (6,7) is y = (1/6)x + 6.