What is the volume, in mL of .089 m lithium chloride (LiCl) solution containing 4.3g of LiCl???
To find the volume of the .089 M lithium chloride solution containing 4.3 g of LiCl, we need to use the formula:
Molarity (M) = moles of solute / volume of solution in liters
First, we need to calculate the number of moles of LiCl. To do this, we use the formula:
moles = mass / molar mass
The molar mass of LiCl is the sum of the atomic masses of lithium (Li) and chlorine (Cl):
molar mass of LiCl = (atomic mass of Li) + (atomic mass of Cl)
The atomic mass of Li is approximately 6.94 g/mol, and the atomic mass of Cl is approximately 35.45 g/mol.
Next, we can calculate the moles of LiCl:
moles = 4.3 g / (6.94 g/mol + 35.45 g/mol)
Now, we can calculate the volume of the solution:
volume = moles / Molarity
As given in the question, the Molarity (M) is 0.089 M.
volume = moles / 0.089 M
Finally, convert the volume from liters to milliliters by multiplying by 1000:
volume in mL = volume in liters * 1000
By following these steps, you should be able to calculate the volume of the lithium chloride solution in mL.