How many different rectangles can you make so that each one has a perimeter of 16 inches?
Formula for perimeter,
P = 2L + 2w
2L + 2w = 16
2(L + w)= 16
L + w = 8
You need numbers that add to 8.
8 + 0 = 8
7 + 1 = 8
6 + 2 = 8
See how many you can come up with.
There might be any easier way, that I'm not thinking about.
Good luck
Cross off 8 + 0 = 8.
Can't have a side of 0.
To find the different rectangles that can have a perimeter of 16 inches, we need to consider the possible combinations of length and width.
Let's assume the length of the rectangle is L and the width is W.
The perimeter of a rectangle is given by the formula:
Perimeter = 2(L + W)
Since we are given that the perimeter is 16 inches, we can rewrite the formula as:
16 = 2(L + W)
Dividing both sides of the equation by 2 gives:
8 = L + W
Now, we need to find all the possible integer solutions for L and W that satisfy this equation.
One approach is to list all the possible combinations of L and W that add up to 8:
L=1, W=7
L=2, W=6
L=3, W=5
L=4, W=4
L=5, W=3
L=6, W=2
L=7, W=1
By considering all the possible values for L and W, we can see that there are seven different rectangles that can have a perimeter of 16 inches.