elimination using multiplication
2m +3n=4
-m + 2n= 5
Please Help!!!!
2m +3n=4
-m + 2n= 5
Multiply by 2 (-m + 2n = 5)
-2m + 4n = 10
2m + 3n = 4
Add the two equation
0 + 7n = 14
7n = 14
n = 2
To find m,
substitute n = 2 in 2m + 3n = 4
and solve for m
I'll let you finish
Check your answers when you find m
2m+3n=4
2m+3*2=4
2m+6=4
2m=4-6
2m= -2 Divide with 2
m= -1
n=2 m= -1
2m +3n=4
Check of results:
2m+3n=4
2*( -1)+3*2=-2+6=4
-m+2n=5
-( -1)+2*2=1+4=5
i ahve no idea i need help!!!!!
To solve this system of equations using the method of elimination, we'll eliminate one variable at a time and solve for the remaining variable. Here's how you can do it:
Step 1: Multiply one or both of the equations by a constant(s) so that the coefficients of one of the variables will be the same in both equations. In this case, multiplying the second equation by 2 will make the coefficients of 'm' the same in both equations:
2m + 3n = 4 (Equation 1)
-2m + 4n = 10 (Multiply Equation 2 by 2)
Simplified equations:
2m + 3n = 4 (Equation 1)
-2m + 4n = 10 (Equation 2)
Step 2: Now, we'll add the two equations together. This will eliminate the 'm' variable because the sum of -2m and 2m is zero:
(2m + 3n) + (-2m + 4n) = 4 + 10
Simplified equation:
7n = 14
Step 3: Divide both sides of the equation by 7 to solve for 'n':
7n/7 = 14/7
Simplified equation:
n = 2
Step 4: Now that we have the value of 'n', we can substitute it back into either of the original equations to solve for 'm'. Let's use Equation 1:
2m + 3n = 4
Substitute n = 2:
2m + 3(2) = 4
Simplified equation:
2m + 6 = 4
Step 5: Subtract 6 from both sides of the equation to isolate 'm':
2m + 6 - 6 = 4 - 6
Simplified equation:
2m = -2
Step 6: Divide both sides of the equation by 2 to solve for 'm':
2m/2 = -2/2
Simplified equation:
m = -1
Therefore, the solution to the system of equations is m = -1 and n = 2.