Please factor
8x^2+18x-5
It would be appreciated if you show the steps. Need this ASAP...Thanks (:
8x^2+18x-5
(2x + 5)(4x - 1)
My method or steps is trial and error.
You need to find factors of 8x^2 that also add to 18x. The same for factors of 5.
It takes practice. The only way you learn is by practice. Do as many problems as you can and eventually it gets easier.
To factor the quadratic expression 8x^2 + 18x - 5, we need to find two binomials whose product results in this expression.
Step 1: Multiply the coefficient of x^2 (8) by the constant term (-5). The result is -40.
Step 2: Find two numbers whose product is -40 and whose sum is the coefficient of x (18). The numbers are 20 and -2.
Step 3: Rewrite the middle term (18x) using the two numbers found in the previous step:
8x^2 + 20x - 2x - 5
Step 4: Group the terms in pairs and factor out the greatest common factor (GCF) from each pair:
(8x^2 + 20x) - (2x + 5)
4x(2x + 5) - 1(2x + 5)
Step 5: Notice that the terms in parentheses (2x + 5) can be factored out:
(4x - 1)(2x + 5)
Therefore, the factored form of 8x^2 + 18x - 5 is (4x - 1)(2x + 5).