Find the variable?
8C + 1 = 7C-2(7+C)
C is the variable.
c=13
Go see my solution for your post at 7:25
To find the variable in the equation 8C + 1 = 7C - 2(7 + C), we need to simplify the equation and isolate the variable. Let's break down the steps:
1. Distribute the -2 to the terms inside the parentheses:
8C + 1 = 7C - 2(7) - 2(C)
This becomes:
8C + 1 = 7C - 14 - 2C
2. Combine like terms on each side of the equation:
8C + 1 = 7C - 2C - 14
Simplifying further:
8C + 1 = 5C - 14
3. Move all the terms with the variable C to one side of the equation by subtracting 5C from both sides:
8C - 5C + 1 = 5C - 5C - 14
This simplifies to:
3C + 1 = -14
4. Next, isolate the variable by moving the constant term to the other side. Subtract 1 from both sides:
3C + 1 - 1 = -14 - 1
Simplifying further:
3C = -15
5. Finally, solve for C by dividing both sides of the equation by 3:
3C / 3 = -15 / 3
This yields the solution:
C = -5
Therefore, the variable C in the given equation is equal to -5.