is y=2^x^2 considered a double exponential function or not?

I believe it is but am not sure since the exponent is x and that is squared. I think to qualify as exponential function wouldn't the x need to be a number and not x?

To determine whether the function y = 2^(x^2) is considered a double exponential function or not, we need to analyze its properties.

An exponential function typically has a constant base raised to the power of a variable. In this case, the base is 2, and the exponent is x^2. While the exponent contains the variable x, it is squared (x^2). It is important to note that in this function, x is still a variable that can take on different values.

A double exponential function, on the other hand, involves exponentiation applied twice to the variable. For example, y = 2^(2^x) is a double exponential function since the variable x is exponentiated twice.

In the given function y = 2^(x^2), we have a single exponentiation operation, with x being squared before being used as the exponent. Therefore, y = 2^(x^2) is not considered a double exponential function. It is still an exponential function since the base 2 is raised to the power of a variable, albeit its variable x is squared.