object weighs 40 N on earth's surface. it would weight on 10 N when its distance from earth's center is
doubled
halved
tripled or
quadrupled
thankyou
To determine how the weight of an object changes with respect to its distance from the Earth's center, we need to understand the concept of gravity. Gravity is the force that pulls objects toward the center of the Earth.
The weight of an object can be calculated using the formula:
Weight = mass × acceleration due to gravity
On the surface of the Earth, the acceleration due to gravity is approximately 9.8 m/s^2. Therefore, for an object with a weight of 40 N:
Weight = mass × 9.8
Now, let's explore how the weight changes when the distance from Earth's center is altered.
1. When the distance is doubled:
To find out what the weight of the object would be if the distance is doubled, we need to consider that the gravitational force decreases with an increase in distance. With a doubled distance, the gravitational force acting on the object decreases by a factor of 1/4 (inverse square law).
So, the weight of the object would be 40 N × (1/4) = 10 N.
2. When the distance is halved:
Similarly, if the distance is halved, the gravitational force acting on the object increases by a factor of 4.
So, the weight of the object would be 40 N × 4 = 160 N.
3. When the distance is tripled:
If the distance is tripled, the gravitational force acting on the object is reduced by a factor of 1/9.
So, the weight of the object would be 40 N × (1/9) = 4.44 N (rounded to two decimal places).
4. When the distance is quadrupled:
If the distance is quadrupled, the gravitational force acting on the object decreases by a factor of 1/16.
So, the weight of the object would be 40 N × (1/16) = 2.5 N (rounded to one decimal place).
Therefore, the weight of the object when the distance from the Earth's center is doubled would be 10 N.