Consider a solid sphere of radius R = 0.52 m that is uniformly charged with ρ = -2.8 µC/m3. What is the electric potential a distance 2.6 m from the center of the sphere?
consider a long cylindrical charge distribution of radius R with a uniform charge density .find the electric field at distance r from the axis where .r<R.
To find the electric potential at a distance 2.6 m from the center of the sphere, we can use the formula for electric potential due to a uniformly charged sphere.
The formula for electric potential at a point outside a uniformly charged sphere is given by:
V = k * (Q / r)
Where:
V is the electric potential at the point,
k is the electrostatic constant (k = 8.99 x 10^9 Nm^2/C^2),
Q is the total charge of the sphere, and
r is the distance from the center of the sphere to the point.
In this case, the sphere is uniformly charged with a charge density of ρ = -2.8 µC/m³. To find the total charge Q of the sphere, we need to integrate the charge density over the volume of the sphere.
Q = ∫ρ dV
Since the sphere is uniformly charged, the total charge Q will be equal to the charge density ρ multiplied by the volume V of the sphere.
V = (4/3) * π * R³
Substituting the given values R = 0.52 m into the equation, we can find the value of V.
Finally, plug the values of Q and r into the formula for electric potential to calculate the electric potential at a distance 2.6 m from the center of the sphere.