# Physics

An airplane must reach a speed of 185 mi/h to take off. If the runway is 467 m long, what is the minimum value of the acceleration that will allow the airplane to take off successfully? m/s2

I have been trying the formula vf^2=Vi^2+2AD and solving for A

SO my work has been

185^2=0^2+2A(467)
34225/934=A
36.643=A

I'm assuming my mistake is using speed as Vf but not sure how else to do it. TIA

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1. Be careful of units.
You expressed the runway length in m (meters), but the takeoff speed is expressed in mi/h (miles/hour). You will need to do some units conversion.

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