3p^2+4P^2=63

3p^2 + 4p^2 = 7p^2

7p^2/7=63/7
p^2=9
√p^2=√9
p=3

3p^2 + 4p^2 = 63

7 p^2 = 63
Divide both sides by 7:
p^2 = 9
Take the square root of both sides:
p = -3 or p = 3

To solve the equation 3p^2 + 4P^2 = 63, we need to find the value(s) of p that satisfy the equation.

Step 1: Combine the like terms on the left side of the equation.
3p^2 + 4p^2 = 63
7p^2 = 63

Step 2: Divide both sides of the equation by 7 to isolate the variable.
(7p^2)/7 = 63/7
p^2 = 9

Step 3: Take the square root of both sides of the equation.
√(p^2) = √9
p = ±3

Therefore, the equation 3p^2 + 4P^2 = 63 has two solutions: p = 3 and p = -3.