using the law of sines, solve the rest of the triangle:

side C=14
side B=4
angle c=145 degrees

i got
angle b= 9.4
angle a=25.6
side A=10.4
but i didn't know if it was correct

sin B/b = sin C/c

sin B = (4/14) sin 145
sin B = .1639
B = 9.42

A = 180 - B - C = 180 - 9.42 - 145 = 25.58
so you have the right idea
Angles are usually upper case, sides lower case.

thanks a bunch!

To solve the rest of the triangle using the Law of Sines, follow these steps:

1. Identify the given parts of the triangle:
- Side C = 14
- Side B = 4
- Angle c = 145 degrees

2. Apply the Law of Sines, which states that the ratio of the sine of an angle to the length of the side opposite that angle is constant in any triangle:

sin(A) / a = sin(B) / b = sin(C) / c

3. Find angle A:
- Since angle C is given as 145 degrees, angle A can be calculated as follows:
- sin(A) / 14 = sin(145) / 4
- sin(A) = (14 / 4) * sin(145)
- sin(A) ≈ 4.36

- However, the value of sin(A) should be between -1 and 1. In this case, it's outside of the valid range. This indicates that the given values result in an impossible triangle, as no triangle can have a sine greater than 1. Hence, the given values are not consistent, and there is no valid solution for the rest of the triangle.

Therefore, your initial calculations were incorrect, as they assumed that a triangle with the given angles and sides was possible.