# pre-calc

is x=15 degrees a solution of radical 3/3 cos2x+sin2x=0

1. 👍
2. 👎
3. 👁
4. ℹ️
5. 🚩
1. By radical 3 do you mean the cube root of (3 cos2x+sin2x) ?

Do you mean cos^2 x and sin^2 x or cos (2x) and sin (2x)?

The cube root will be zero if and only if 3cos2x+sin2x is also zero. Put in 15 degrees for x and see what you get.

1. 👍
2. 👎
3. ℹ️
4. 🚩

## Similar Questions

Which of the following are identities? Check all that apply. (Points : 2) sin2x = 1 - cos2x sin2x - cos2x = 1 tan2x = 1 + sec2x cot2x = csc2x - 1 Question 4. 4. Which of the following equations are identities? Check all that

2. ### dai so

chung minh dang thuc (1+Sin2x)/Cos2x=Tan(pi/4+x)

3. ### Trigonometry

find sin2x, cos2x, and tan2x if sinx= -2/sqrt 5 and x terminates in quadrant III

4. ### trigonometry

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and sin2y=2sinycosy; ....)

1. ### calc

sin2x = (radical 3)/ 2 solve each equation on the interval [0,2pi)

2. ### pre-calculus

tanx= -12/5 x in quadrant 2 find; sin2x= cos2x= tan2x=

Express sec2x in terms of tanx and secx I know you have to sec(2x) = 1/cos(2x) = 1/(cos²x - sin²x) But how do you split that. Like how to simplify that?

4. ### math

d2y/dx2+9y=cos2x+sin2x

1. ### Math

Solve the equation sin2x=2cos2x, for 0 degrees

2. ### PreCalculus

Sin5x cos2x + cos5x sin2x=

3. ### calculus

find sin2x, cos2x, and tan2x if sinx= -1/sqrt 5 and x terminates in quadrant II

4. ### math

angle x lies in the third quadrant and tanx=7/24 determiner an exact value for cos2x determiner an exact value for sin2x