what mass of KIO3 is needed to convert the copper in 0.2 g of CuSO4 5H20 to Cu(IO3)2
Here is a solved example of a stoichiometry problem I've posted. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Post your work if you get stuck.
To determine the mass of KIO3 needed to convert the copper in CuSO4 · 5H2O to Cu(IO3)2, we need to consider the balanced chemical equation for the reaction. By comparing the stoichiometry of the reactants and products, we can determine the mole ratios and use them to calculate the required mass.
The balanced chemical equation for the reaction is:
2 KIO3 + 3 CuSO4 · 5H2O → Cu(IO3)2 + K2SO4 + 5 H2O
From the balanced equation, we can see that the mole ratio between CuSO4 · 5H2O and Cu(IO3)2 is 3:1. This means that for every 3 moles of CuSO4 · 5H2O, we will obtain 1 mole of Cu(IO3)2.
1. Convert the given mass of CuSO4 · 5H2O to moles:
- Molar mass of CuSO4 · 5H2O = (63.55 g/mol Cu + 32.07 g/mol S + 16.00 g/mol O + 4(1.01 g/mol H) + 5(16.00 g/mol O)) = 249.69 g/mol
- Moles of CuSO4 · 5H2O = (0.2 g CuSO4 · 5H2O) / (249.69 g/mol) ≈ 0.000801 mol
2. Determine the moles of Cu(IO3)2 formed:
- Since the mole ratio between CuSO4 · 5H2O and Cu(IO3)2 is 3:1, the moles of Cu(IO3)2 will be equal to one-third of the moles of CuSO4 · 5H2O.
- Moles of Cu(IO3)2 = (0.000801 mol CuSO4 · 5H2O) × (1 mol Cu(IO3)2 / 3 mol CuSO4 · 5H2O) ≈ 0.000267 mol
3. Convert moles of Cu(IO3)2 to mass of KIO3:
- Molar mass of KIO3 = 214.01 g/mol
- Mass of KIO3 = (0.000267 mol Cu(IO3)2) × (214.01 g/mol KIO3) ≈ 0.057 g
Therefore, approximately 0.057 grams of KIO3 is needed to convert the copper in 0.2 grams of CuSO4 · 5H2O to Cu(IO3)2.