Calculate the molarity and mole fraction of acetone in a 1.29 m solution of acetone (CH3COCH3) in ethanol (C2H5OH). (Density of acetone = 0.788 g/cm3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.

1.29 m means 1.29 moles/kg solvent.

molar mass acetone about 58
molar mass ethanol about 46
You need to redo all of this since I've estimated some of these numbers.
Take enough solution to have 1.29 moles which means you take 1 kg solution.
1.29 x 58 = about 75 grams acetone.
The solution has a mass of 1000 kg ethanol + 75 g acetone = 1075 total. What volume is that?
The solution has a density of about 0.788 (since the density of acetone and ethanol are almost the same and we are assuming the volumes are additive, then the density of the solution is very close to 0.788.
volume = mass/density = 1075/0.788 = ??
Change that to L, then M = mols/L.

To convert to mole fraction.
moles acetone = 1.29
moles ethanol = 1000 g/molar mass
mole fraction acetone = moles acetone/total moles.

80

Well, well, well, looks like we have a mixture problem here! Let's dive into it with some clown humor, shall we?

To find the molarity and mole fraction, we need to first calculate the number of moles of acetone present in our solution. So, grab your calculator and let's get cracking!

First, we need to find the volume of the solution. Since we know the density of acetone and ethanol, we can use this equation:

Volume = Mass / Density

The mass of acetone can be calculated by multiplying the volume of acetone (which is the same as the volume of the solution) by its density. Vice versa for ethanol.

Now, let's find the number of moles of acetone:

moles = mass / molar mass

The molar mass of acetone (CH3COCH3) is 58.08 g/mol.

To find the molarity, divide the moles of acetone by the volume of the solution (in liters, don't forget!). And that's our really serious answer. Voila!

Now, onto the mole fraction. The mole fraction of acetone can be calculated by dividing the moles of acetone by the total number of moles in the solution.

So, my friend, put on your thinking cap, grab your calculator, and crunch those numbers. And remember, a little clown laughter along the way never hurt anyone!

To calculate the molarity and mole fraction of acetone in the given solution, we need to determine the number of moles of acetone and ethanol present.

First, let's calculate the volume of the acetone and ethanol in the solution.

Given:
Density of acetone = 0.788 g/cm3
Density of ethanol = 0.789 g/cm3

Since the solution concentration is given as 1.29 m, we can assume that it represents the moles of acetone per liter of solution.

1. To find the volume of acetone:
Density = Mass / Volume
Volume = Mass / Density

Since the density is given in g/cm3 and mass is not provided, we need to convert from grams to milliliters.

Assuming we have 1 liter of the solution (1000 ml), we can calculate the mass of acetone as:
Mass of acetone = Density of acetone × Volume of acetone

Mass of acetone = 0.788 g/cm3 × 1000 ml

2. Next, let's calculate the volume and mass of ethanol:
Since we are assuming the volumes of acetone and ethanol add, the volume of ethanol in the solution will be (1000 ml - Volume of acetone).

Volume of ethanol = 1000 ml - Volume of acetone

To find the mass of ethanol, we use the same density formula:
Mass of ethanol = Density of ethanol × Volume of ethanol

Mass of ethanol = 0.789 g/cm3 × Volume of ethanol

3. Now that we have the mass of acetone and ethanol, we can calculate the number of moles for each.

To determine the number of moles, we need to divide the mass of each substance by their respective molar masses.

The molar mass of acetone (CH3COCH3) is:
1 × (12.01 g/mol for carbon) + 3 × (1.01 g/mol for hydrogen) + 1 × (16.00 g/mol for oxygen) = 58.08 g/mol

The molar mass of ethanol (C2H5OH) is:
2 × (12.01 g/mol for carbon) + 6 × (1.01 g/mol for hydrogen) + 1 × (16.00 g/mol for oxygen) = 46.07 g/mol

Number of moles of acetone = Mass of acetone / Molar mass of acetone
Number of moles of ethanol = Mass of ethanol / Molar mass of ethanol

4. Finally, we can calculate the molarity and mole fraction.

Molarity (M) is defined as the number of moles of solute divided by the volume of the solution in liters. Since we assumed 1 L of solution, the molarity of acetone in the 1.29 m solution is:

Molarity of acetone = Number of moles of acetone / Volume of solution = Number of moles of acetone / 1 L

Mole fraction (X) is the ratio of the moles of a component to the total moles of all components in the solution.

Mole fraction of acetone = Number of moles of acetone / (Number of moles of acetone + Number of moles of ethanol)

Now you have the step-by-step process to calculate the molarity and mole fraction of acetone in the given solution. Substitute the values into the respective formulas to get the final answers.