Calculus

find the equation of a line tangent to the graph of y = x / (square root of 5x^s +4), at x = 1.

am i suppose to take the derivative? if so, then what else?

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  1. yes
    take the derivative and sub x=1 into that, giving you the slope of the tangent

    also sub x=1 into the original equation to get y, so then you have the slope of the tangent and the point of contact.

    Can you find the equation of a line given the slope and a point on it??

    BTW, is that supposed to say.. 5x^2 +4 ?

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